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===== Multi-class classification in scikit-learn =====
Let's use a One-vs-the-rest classifier on the [[https://archive.ics.uci.edu/ml/datasets/Iris | iris dataset]]. The data has four features that describe features of three types of iris flowers.
In [1]: import numpy as np
In [2]: from sklearn import datasets
In [3]: from sklearn.multiclass import OneVsRestClassifier,OneVsOneClassifier
In [4]: from sklearn.svm import LinearSVC,SVC
In [5]: from sklearn import cross_validation
In [6]: iris = datasets.load_iris()
In [7]: X, y = iris.data, iris.target
In [8]: classifier = OneVsRestClassifier(LinearSVC())
In [9]: print np.mean(cross_validation.cross_val_score(classifier, X, y, cv=5))
0.966666666667
In [10]: classifier = OneVsOneClassifier(LinearSVC())
In [11]: print np.mean(cross_validation.cross_val_score(classifier, X, y, cv=5))0.98
In [12]: # does this mean that oneVsOne is better? not necessarily...
In [13]: classifier = OneVsRestClassifier(SVC(C=1, kernel='rbf', gamma=0.5))
In [14]: print np.mean(cross_validation.cross_val_score(classifier, X, y, cv=5))0.98
And here's the code without the python prompts to get in the way:
import numpy as np
from sklearn import datasets
from sklearn.multiclass import OneVsRestClassifier,OneVsOneClassifier
from sklearn.svm import LinearSVC,SVC
from sklearn import cross_validation
iris = datasets.load_iris()
X, y = iris.data, iris.target
classifier = OneVsRestClassifier(LinearSVC())
print np.mean(cross_validation.cross_val_score(classifier, X, y, cv=5))
classifier = OneVsOneClassifier(LinearSVC())
print np.mean(cross_validation.cross_val_score(classifier, X, y, cv=5))
# does this mean that oneVsOne is better? not necessarily...
classifier = OneVsRestClassifier(SVC(C=1, kernel='rbf', gamma=0.5))
print np.mean(cross_validation.cross_val_score(classifier, X, y, cv=5))