Let n be a positive integer.
Consider the first n+1 integers in the sequence
(7, 77, 777, 7777, ..., ). Each of these n+1 numbers
has only n possible remainders
when divide by n, so two of them must have the same remainder
by the pigeonhole principle.
The difference of these two is a jackpot and divisible by n.
Correct solutions: Bob Liebler, Ben Manvel (faculty),
Florian Hulpke (University of Hannover), Byungsoo Kim (Seoul),
Julien Gaigneur (Cellzome Corp., Heidelberg)