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tutorial_lud [2015/10/06 16:10]
sanjay
tutorial_lud [2015/10/06 16:12]
sanjay [Step 3 : Equations]
Line 143: Line 143:
 L = case L = case
    {i,j|1==j} : (A / (i,j->j,j)@U);    {i,j|1==j} : (A / (i,j->j,j)@U);
-   {i,j|1<i} : (A - reduce(+, (i,j,k->i,j), (i,j,k->i,k)@L*(i,j,k->k,j)@U))/(i,j->i,i)@U;+   {i,j|1<i} : (A - reduce(+, (i,j,k->i,j), (i,j,k->i,k)@L*(i,j,k->k,j)@U))/(i,j->j,j)@U;
 esac; esac;
 </sxh> </sxh>
tutorial_lud.txt ยท Last modified: 2019/04/05 09:02 by sanjay