#include <stdio.h>


int f3(int n) {
    int c = 0;
    for (int step = n; step > 0; step /= 3)
	for (int i = 0; i < step; i++)
	    c++;
    return c;
}

int main() {
    for (int n=10; n<1000000; n*=1.9)
	printf("%9d %9d %9d\n", n, f3(n), n*3/2);
    return 0;
}